Can you fellers take your whining pissing contest to email? "John S" <Sophi.2@invalid.org> wrote in message = news:jg5123$v2i$1@dont-email.me...> On 1/29/2012 8:50 PM, Phil Allison wrote: > > "John Smith Radio Ham KD5YI =3D CUNTHEAD" > > > > > >>>> According to chart on the data sheet you posted, the device is =not> >>>> useable > >>>> at all. > >>> > >>> > >>> ** Go telk the makers that one - > >>> >=20 > > > >>> > >> Well, you brought it up. > > > > > > ** It's YOUR * claim - >=20 > It is no more my claim than yours, Phil. But you cut the relevant =parts.=20> Maybe because you have no valid argument. It's difficult to understand => how your demented mind works. >=20 > Try to have a nice day. >=20 >=20 >=20 >=20 >=20 >=20 >
Current transformer
Started by ●November 30, 2011
Reply by ●January 29, 20122012-01-29
Reply by ●January 29, 20122012-01-29
"John Smith Radio Ham KD5YI = CUNTHEAD">>> According to chart on the data sheet you posted, the device is not >>> useable at all. >> >> >> ** Go telk the makers that one - >> >> you stinking pile of festering septic shit.>> > Well, you brought it up.** It's YOUR * FUCKWIT * claim - you stinking, radio ham CUNT HEAD !!! You need shooting - pal.
Reply by ●January 29, 20122012-01-29
"Guv Bob" Can you fellers take your whining pissing contest to email? ** The ham radio fuckwit abuses people in a public, so any response to him has to be too. KD5YI is a trolling, trouble making nutter who needs to be booted off usenet immediately. And you are no net cop. .... Phil
Reply by ●January 29, 20122012-01-29
On 1/29/2012 9:03 PM, Phil Allison wrote:> "John Smith Radio Ham KD5YI = CUNTHEAD" > > >>>> According to chart on the data sheet you posted, the device is not >>>> useable at all. >>> >>> >>> ** Go telk the makers that one - >>> >>> you stinking pile of festering septic shit. > >>> >> Well, you brought it up. > > > ** It's YOUR * FUCKWIT * claim - > > you stinking, radio ham CUNT HEAD !!! > > You need shooting - pal.[snicker] Okay, meet me at dawn. Your choice of pistols.
Reply by ●January 29, 20122012-01-29
On 1/29/2012 9:02 PM, Guv Bob wrote:> Can you fellers take your whining pissing contest to email?Can you just read another thread and ignore this one?
Reply by ●January 30, 20122012-01-30
On Sun, 29 Jan 2012 18:07:14 -0600, John S <Sophi.2@invalid.org> wrote:>On 1/29/2012 4:13 PM, boB wrote: >> On Sun, 29 Jan 2012 08:23:40 -0800 (PST), whit3rd<whit3rd@gmail.com> >> wrote: >> >>> On Saturday, January 28, 2012 6:33:12 PM UTC-8, John S wrote: >>>> On 1/28/2012 7:52 PM, josephkk wrote: >>>>> On Mon, 23 Jan 2012 22:29:51 -0500, DJ Delorie<d...@delorie.com> =wrote:>>>> >>>>> That is not all, maybe not even the most important. The flux in =the core>>>>> when operated properly in the CT mode is nearly zero, >>>> >>>> Not true. There is flux in the core no matter what. It is what gives >>>> rise to a secondary voltage across a resistor. >>> >>> Irrelevant. The flux is proportional to the voltage drop, both ON =THE>>> PRIMARY and on the secondary. Your intent is to have zero voltage >>> drop on the primary, SO all the current transformer design criteria >>> are to make that flux (and d(flux)/dt) as small as practical. >>> >>> To make a CT design truly ideal, it's frequently useful to use op =amps>>> to make a zero-ohm (or negative resistance) load for the secondary. >>> Low resistance load resistors are not just a compromise, they are a >>> USEFUL compromise. Don't think they're irrelevant. >> >> >> Just realize that IxR drop on the copper does not contribute to >> volt-seconds on the core, (B) , which is why drawing current >> on a winding of an unregulated voltage transformer, like a wall >> wart, will actually lower the flux density. >> >> boB >> K7IQ > >Yes, and the secondary voltage as well.Yes, now think it through clearly. I did not say zero but nearly zero. ?-)
Reply by ●January 30, 20122012-01-30
On Sun, 29 Jan 2012 03:08:57 -0500, legg <legg@nospam.magma.ca> wrote:>On Sat, 28 Jan 2012 17:52:15 -0800, josephkk ><joseph_barrett@sbcglobal.net> wrote: > >>On Mon, 23 Jan 2012 22:29:51 -0500, DJ Delorie <dj@delorie.com> wrote: >> >>> >>>"vkj" <tranquine@n_o_s_p_a_m.n_o_s_p_a_m.gmail.com> writes: >>>> Why? I dont understand why one cant simply use the open ckt voltage=on the>>>> secondary as a measure of the primary current. Heres my argument: >>> >>>Because a current transformer is normally in the 1000:1 range. Do you >>>really want to try to measure 120,000 volts? >>> >>>(also: this is why it's important to hook up the load resistor =*before*>>> you put the current transformer on the primary wire) >> >>That is not all, maybe not even the most important. The flux in the =core>>when operated properly in the CT mode is nearly zero, and if the =secondary>>is open that is NOT true, and the core could easily saturate. BTW the >>relevant IEEE standards make a distinction between metering and >>protection/relaying CT and their performance properties in overload. >> >>?-) >The physical implimentation of both current and voltage transformers >is a compromise determined by material characteristics and cost. The >important thing is that the final physical iteration performs >repeatably as required, within a practical budget, with a full >understanding of it's limitations under non-optimal conditions. > >No transformer is actually useful under 'ideal' short circuit or >'ideal' open circuit conditions. > >RLUmmm, well maybe the extremely few that are designed to be operated that way. It is very few. ?-)
Reply by ●January 30, 20122012-01-30
On Sat, 28 Jan 2012 19:56:36 -0800, John Larkin <jjlarkin@highNOTlandTHIStechnologyPART.com> wrote:>On Sat, 28 Jan 2012 19:30:48 -0800, josephkk ><joseph_barrett@sbcglobal.net> wrote: > >>On Sat, 28 Jan 2012 18:12:46 -0800, John Larkin >><jjlarkin@highNOTlandTHIStechnologyPART.com> wrote: >> >>>On Sat, 28 Jan 2012 18:01:11 -0800, josephkk >>><joseph_barrett@sbcglobal.net> wrote: >>> >>>>On Tue, 24 Jan 2012 21:47:41 -0600, "vkj" >>>><tranquine@n_o_s_p_a_m.n_o_s_p_a_m.gmail.com> wrote: >>>> >>>>>>On 2/12/2011 11:57 AM, Tim Williams wrote: >>>>>>> Actually Jim, that's exactly the problem. >>>>>>> >>>>>>> A high impedance load will work perfectly. >>>>>> >>>>>>Only as long as the primary current doesn't drive the core into >>>>>saturation. >>>>>> >>>>>>Sylvia. >>>>>> >>>>> >>>>>Lets not confuse the focus of the issue and consider air cores only,=thus>>>>>eliminating saturation. >>>>> >>>>>Lets say your current transformer presents an impedance of 1 =milli-Ohm.=20>>>>>Lets say your current is 20A. The prim. voltage is then 20mV. As =someone>>>>>has pointed out the turns ratio of a typical CT could be 1000:1, so =the>>>>>sec. open circuit volt is still just 20V. Hardly disastrous. >>>>> >>>>>vkj =20 >>>> >>>>Wrong and wrong. The primary impedance applies _ONLY_ when the =secondary>>>>is terminated with a proper load (resistor). Otherwise it becomes an >>>>ordinary voltage transformer, and the primary voltage is no longer in=the>>>>mV range, but in the volts range, with corresponding kV across the >>>>secondary. >>>> >>> >>>If I may borrow a quotation, "Wrong and wrong." >>> >>>http://en.wikipedia.org/wiki/Rogowski_coil >> >>Not a "normal" current transformer in case you hadn't noticed. >> >>?-) > >We were discussing air-core CTs.=20Since when? ?-)
Reply by ●January 30, 20122012-01-30
On Mon, 30 Jan 2012 01:21:27 -0800, josephkk <joseph_barrett@sbcglobal.net> wrote:>On Sat, 28 Jan 2012 19:56:36 -0800, John Larkin ><jjlarkin@highNOTlandTHIStechnologyPART.com> wrote: > >>On Sat, 28 Jan 2012 19:30:48 -0800, josephkk >><joseph_barrett@sbcglobal.net> wrote: >> >>>On Sat, 28 Jan 2012 18:12:46 -0800, John Larkin >>><jjlarkin@highNOTlandTHIStechnologyPART.com> wrote: >>> >>>>On Sat, 28 Jan 2012 18:01:11 -0800, josephkk >>>><joseph_barrett@sbcglobal.net> wrote: >>>> >>>>>On Tue, 24 Jan 2012 21:47:41 -0600, "vkj" >>>>><tranquine@n_o_s_p_a_m.n_o_s_p_a_m.gmail.com> wrote: >>>>> >>>>>>>On 2/12/2011 11:57 AM, Tim Williams wrote: >>>>>>>> Actually Jim, that's exactly the problem. >>>>>>>> >>>>>>>> A high impedance load will work perfectly. >>>>>>> >>>>>>>Only as long as the primary current doesn't drive the core into >>>>>>saturation. >>>>>>> >>>>>>>Sylvia. >>>>>>> >>>>>> >>>>>>Lets not confuse the focus of the issue and consider air cores only, thus >>>>>>eliminating saturation. >>>>>> >>>>>>Lets say your current transformer presents an impedance of 1 milli-Ohm. >>>>>>Lets say your current is 20A. The prim. voltage is then 20mV. As someone >>>>>>has pointed out the turns ratio of a typical CT could be 1000:1, so the >>>>>>sec. open circuit volt is still just 20V. Hardly disastrous. >>>>>> >>>>>>vkj >>>>> >>>>>Wrong and wrong. The primary impedance applies _ONLY_ when the secondary >>>>>is terminated with a proper load (resistor). Otherwise it becomes an >>>>>ordinary voltage transformer, and the primary voltage is no longer in the >>>>>mV range, but in the volts range, with corresponding kV across the >>>>>secondary. >>>>> >>>> >>>>If I may borrow a quotation, "Wrong and wrong." >>>> >>>>http://en.wikipedia.org/wiki/Rogowski_coil >>> >>>Not a "normal" current transformer in case you hadn't noticed. >>> >>>?-) >> >>We were discussing air-core CTs. > >Since when? > >?-)Since vkj's response to Sylvia. -- John Larkin, President Highland Technology Inc www.highlandtechnology.com jlarkin at highlandtechnology dot com Precision electronic instrumentation Picosecond-resolution Digital Delay and Pulse generators Custom timing and laser controllers Photonics and fiberoptic TTL data links VME analog, thermocouple, LVDT, synchro, tachometer Multichannel arbitrary waveform generators
Reply by ●January 31, 20122012-01-31
On Mon, 30 Jan 2012 07:16:21 -0800, John Larkin <jjlarkin@highNOTlandTHIStechnologyPART.com> wrote:>On Mon, 30 Jan 2012 01:21:27 -0800, josephkk ><joseph_barrett@sbcglobal.net> wrote: > >>On Sat, 28 Jan 2012 19:56:36 -0800, John Larkin >><jjlarkin@highNOTlandTHIStechnologyPART.com> wrote: >> >>>On Sat, 28 Jan 2012 19:30:48 -0800, josephkk >>><joseph_barrett@sbcglobal.net> wrote: >>> >>>>On Sat, 28 Jan 2012 18:12:46 -0800, John Larkin >>>><jjlarkin@highNOTlandTHIStechnologyPART.com> wrote: >>>> >>>>>On Sat, 28 Jan 2012 18:01:11 -0800, josephkk >>>>><joseph_barrett@sbcglobal.net> wrote: >>>>> >>>>>>On Tue, 24 Jan 2012 21:47:41 -0600, "vkj" >>>>>><tranquine@n_o_s_p_a_m.n_o_s_p_a_m.gmail.com> wrote: >>>>>> >>>>>>>>On 2/12/2011 11:57 AM, Tim Williams wrote: >>>>>>>>> Actually Jim, that's exactly the problem. >>>>>>>>> >>>>>>>>> A high impedance load will work perfectly. >>>>>>>> >>>>>>>>Only as long as the primary current doesn't drive the core into >>>>>>>saturation. >>>>>>>> >>>>>>>>Sylvia. >>>>>>>> >>>>>>>>>>>>>>Lets not confuse the focus of the issue and consider air cores =only, thus>>>>>>>eliminating saturation. >>>>>>> >>>>>>>Lets say your current transformer presents an impedance of 1 =milli-Ohm.=20>>>>>>>Lets say your current is 20A. The prim. voltage is then 20mV. As=someone>>>>>>>has pointed out the turns ratio of a typical CT could be 1000:1, =so the>>>>>>>sec. open circuit volt is still just 20V. Hardly disastrous. >>>>>>> >>>>>>>vkj =20>>>>>> >>>>>>Wrong and wrong. The primary impedance applies _ONLY_ when the =secondary>>>>>>is terminated with a proper load (resistor). Otherwise it becomes =an>>>>>>ordinary voltage transformer, and the primary voltage is no longer =in the>>>>>>mV range, but in the volts range, with corresponding kV across the >>>>>>secondary. >>>>>> >>>>> >>>>>If I may borrow a quotation, "Wrong and wrong." >>>>> >>>>>http://en.wikipedia.org/wiki/Rogowski_coil >>>> >>>>Not a "normal" current transformer in case you hadn't noticed. >>>> >>>>?-) >>> >>>We were discussing air-core CTs.=20 >> >>Since when? >> >>?-) > >Since vkj's response to Sylvia.Nope. Go read the thread again, you inserted Rogowski coils (for the second time)
