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What's the term for this?

Started by Chris March 27, 2016
Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA 
but I want to push it to a higher power but at a lower duty cycle. What's 
the fancy term for that?
On 3/27/2016 12:06 PM, Chris wrote:
> Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA > but I want to push it to a higher power but at a lower duty cycle. What's > the fancy term for that?
Duty cycle? -- Rick
On Sun, 27 Mar 2016 16:06:56 -0000 (UTC), Chris <cbx@noreply.com>
wrote:

>Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA >but I want to push it to a higher power but at a lower duty cycle. What's >the fancy term for that?
Pulsing. -- John Larkin Highland Technology, Inc lunatic fringe electronics
On Sun, 27 Mar 2016 10:18:58 -0700, John Larkin wrote:

> On Sun, 27 Mar 2016 16:06:56 -0000 (UTC), Chris <cbx@noreply.com> > wrote: > >>Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA >>but I want to push it to a higher power but at a lower duty cycle. >>What's the fancy term for that? > > Pulsing.
No, that's not the thing here. It's something similar to "de-rating" if that makes any sense?
On Sun, 27 Mar 2016 19:01:39 -0000 (UTC), Chris <cbx@noreply.com>
wrote:

>On Sun, 27 Mar 2016 10:18:58 -0700, John Larkin wrote: > >> On Sun, 27 Mar 2016 16:06:56 -0000 (UTC), Chris <cbx@noreply.com> >> wrote: >> >>>Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA >>>but I want to push it to a higher power but at a lower duty cycle. >>>What's the fancy term for that? >> >> Pulsing. > >No, that's not the thing here. It's something similar to "de-rating" if >that makes any sense?
Pulse mode. Your putting in the same amount of Joules over the same period as continuous duty mode. It doesnot sound like you can use the other terms such as Pulse Pumping or mode-locking in your application. Cheers
On Sun, 27 Mar 2016 16:06:56 -0000 (UTC), Chris <cbx@noreply.com>
wrote:

>Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA >but I want to push it to a higher power but at a lower duty cycle. What's >the fancy term for that?
Why do you want to do that? -- John Larkin Highland Technology, Inc lunatic fringe electronics
>Why do you want to do that?
To help the economy by blowing up lasers, of course. I expect he'll discover why that is a much less good idea than it seems. Cheers Phil Hobbs
>">Why do you want to do that? > >To help the economy by blowing up lasers, of course."
That's what I was thinking.
On Sun, 27 Mar 2016 13:04:10 -0700 (PDT), Phil Hobbs
<pcdhobbs@gmail.com> wrote:

>>Why do you want to do that? > >To help the economy by blowing up lasers, of course. I expect he'll discover why that is a much less good idea than it seems.
A different take on the "broken windows" theory, I suppose.
On Sun, 27 Mar 2016 12:46:30 -0700, John Larkin wrote:

> On Sun, 27 Mar 2016 16:06:56 -0000 (UTC), Chris <cbx@noreply.com> > wrote: > >>Say I have a laser diode rated for continuous duty at a Vf=4.5V @ 500mA >>but I want to push it to a higher power but at a lower duty cycle. >>What's the fancy term for that? > > Why do you want to do that?
At the risk of net-cop Phil Hobbs overhearing and reporting me to the Feds, I want to know how much I can exceed the rated constant duty V & A if I operate the diode at a much lower duty cycle (say 15%). Is there a formula for this sort of thing?