Forums

wave and rider

Started by Jon January 25, 2013
This is the signal I hope to create:

https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534278810_133123559_n.jpg

both the frequency of the blue wave and the frequency of the red rider wave 
are adjustable.

I came up with the equation for the wave using vector calculus, but it is 
unlikely that the math decoder can crunch out a signal in real time at the 
press of a key.

x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
y(t) = 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))

any ideas?

Jon 

It doesn't loop back on itself, so you're going to have a difficult time 
drawing that on an X-Y plot.

Tim

-- 
Deep Friar: a very philosophical monk.
Website: http://seventransistorlabs.com

"Jon" <no-reply@no-reply.com> wrote in message 
news:zipMs.105310$EO2.72687@newsfe04.iad...
> This is the signal I hope to create: > > https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534278810_133123559_n.jpg > > both the frequency of the blue wave and the frequency of the red rider > wave are adjustable. > > I came up with the equation for the wave using vector calculus, but it > is unlikely that the math decoder can crunch out a signal in real time > at the press of a key. > > x(t) = t + (6*cos(t))*(0.5*(sin( > 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) > y(t) = 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) > > any ideas? > > Jon
Tim Williams wrote:
> It doesn't loop back on itself, so you're going to have a difficult time > drawing that on an X-Y plot. > > Tim >
...just use a polarity inverter on the time axis.
On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon"
<no-reply@no-reply.com> wrote in <zipMs.105310$EO2.72687@newsfe04.iad>:

>This is the signal I hope to create: > >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534278810_133123559_n.jpg > >both the frequency of the blue wave and the frequency of the red rider wave >are adjustable. > >I came up with the equation for the wave using vector calculus, but it is >unlikely that the math decoder can crunch out a signal in real time at the >press of a key. > >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) >y(t) = 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) > >any ideas? > >Jon
Backward in time? The waves with a knot in them are the most difficult. Try an xy scope :-)
On Jan 25, 5:38=A0am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote:
> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon" > <no-re...@no-reply.com> wrote in <zipMs.105310$EO2.72...@newsfe04.iad>: > > > > > > >This is the signal I hope to create: > > >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534... > > >both the frequency of the blue wave and the frequency of the red rider w=
ave
> >are adjustable. > > >I came up with the equation for the wave using vector calculus, but it i=
s
> >unlikely that the math decoder can crunch out a signal in real time at t=
he
> >press of a key. > > >x(t) =3D t + (6*cos(t))*(0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^=
.5)))
> >y(t) =3D 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))=
)
> > >any ideas? > > >Jon > > Backward in time?
Yeah I'm confused by what he means by signal.
> The waves with a knot in them are the most difficult. > Try an xy scope :-)- Hide quoted text - > > - Show quoted text -
"Jon" <no-reply@no-reply.com> wrote in
news:zipMs.105310$EO2.72687@newsfe04.iad: 

> https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_1015135353427 > 8810_133123559_n.jpg
Ah!! you want a signal to back and forth in time!! At last timetravel in both directions solved!!
On Fri, 25 Jan 2013 07:24:35 -0800, George Herold wrote:

> On Jan 25, 5:38&nbsp;am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote: >> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon" >> <no-re...@no-reply.com> wrote in <zipMs.105310$EO2.72...@newsfe04.iad>: >> >> >> >> >> >> >This is the signal I hope to create: >> >> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/
s480x480/2049_10151353534...
>> >> >both the frequency of the blue wave and the frequency of the red rider >> >wave are adjustable. >> >> >I came up with the equation for the wave using vector calculus, but it >> >is unlikely that the math decoder can crunch out a signal in real time >> >at the press of a key. >> >> >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) >> >))*(1/((1+36*((cos(t))^2))^.5))) y(t) = 6*sin(t) - (0.5*(sin( >> >25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) >> >> >any ideas? >> >> >Jon >> >> Backward in time? > > Yeah I'm confused by what he means by signal.
If it's a wiggly line on something that looks like a scope screen, then it must be a signal. (Jon: signals and functions are closely related. If your signal isn't a function in time, then it's not a signal, either. That "signal" has more than one value of y for most values of x. So while it is a valid curve, as plotted it isn't really a signal). -- My liberal friends think I'm a conservative kook. My conservative friends think I'm a liberal kook. Why am I not happy that they have found common ground? Tim Wescott, Communications, Control, Circuits & Software http://www.wescottdesign.com

"Tim Wescott" <tim@seemywebsite.com> wrote in message 
news:ltKdnY-LaNH3I5_MnZ2dnUVZ_uudnZ2d@giganews.com...
> On Fri, 25 Jan 2013 07:24:35 -0800, George Herold wrote: > >> On Jan 25, 5:38 am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote: >>> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon" >>> <no-re...@no-reply.com> wrote in <zipMs.105310$EO2.72...@newsfe04.iad>: >>> >>> >>> >>> >>> >>> >This is the signal I hope to create: >>> >>> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/ > s480x480/2049_10151353534... >>> >>> >both the frequency of the blue wave and the frequency of the red rider >>> >wave are adjustable. >>> >>> >I came up with the equation for the wave using vector calculus, but it >>> >is unlikely that the math decoder can crunch out a signal in real time >>> >at the press of a key. >>> >>> >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) >>> >))*(1/((1+36*((cos(t))^2))^.5))) y(t) = 6*sin(t) - (0.5*(sin( >>> >25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) >>> >>> >any ideas? >>> >>> >Jon >>> >>> Backward in time? >> >> Yeah I'm confused by what he means by signal. > > If it's a wiggly line on something that looks like a scope screen, then > it must be a signal. > > (Jon: signals and functions are closely related. If your signal isn't a > function in time, then it's not a signal, either. That "signal" has more > than one value of y for most values of x. So while it is a valid curve, > as plotted it isn't really a signal). > > -- > My liberal friends think I'm a conservative kook. > My conservative friends think I'm a liberal kook. > Why am I not happy that they have found common ground? > > Tim Wescott, Communications, Control, Circuits & Software > http://www.wescottdesign.com
https://sphotos-b.xx.fbcdn.net/hphotos-ash3/s480x480/602730_10151354609363810_2113498556_n.jpg
On 25/01/2013 20:19, Jon wrote:
> > > "Tim Wescott" <tim@seemywebsite.com> wrote in message > news:ltKdnY-LaNH3I5_MnZ2dnUVZ_uudnZ2d@giganews.com... >> On Fri, 25 Jan 2013 07:24:35 -0800, George Herold wrote: >> >>> On Jan 25, 5:38 am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote: >>>> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon" >>>> <no-re...@no-reply.com> wrote in <zipMs.105310$EO2.72...@newsfe04.iad>: >>>> >>>> >This is the signal I hope to create: >>>> >>>> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/ >> s480x480/2049_10151353534...
It is multivalued for various t how exactly do you expect your hardware to output more than one voltage at a single port?
>>>> >>>> >both the frequency of the blue wave and the frequency of the red rider >>>> >wave are adjustable. >>>> >>>> >I came up with the equation for the wave using vector calculus, but it >>>> >is unlikely that the math decoder can crunch out a signal in real time >>>> >at the press of a key. >>>> >>>> >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) >>>> >))*(1/((1+36*((cos(t))^2))^.5))) y(t) = 6*sin(t) - (0.5*(sin( >>>> >25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))) >>>> >>>> >any ideas? >>>> >>>> >Jon >>>> >>>> Backward in time? >>> >>> Yeah I'm confused by what he means by signal. >> >> If it's a wiggly line on something that looks like a scope screen, then >> it must be a signal. >> >> (Jon: signals and functions are closely related. If your signal isn't a >> function in time, then it's not a signal, either. That "signal" has more >> than one value of y for most values of x. So while it is a valid curve, >> as plotted it isn't really a signal). >> >> -- >> My liberal friends think I'm a conservative kook. >> My conservative friends think I'm a liberal kook. >> Why am I not happy that they have found common ground? >> >> Tim Wescott, Communications, Control, Circuits & Software >> http://www.wescottdesign.com > > https://sphotos-b.xx.fbcdn.net/hphotos-ash3/s480x480/602730_10151354609363810_2113498556_n.jpg
That one is carefully chosen so that y(t) vs x(t) has only one value. You need to think very carefully about what it is you are trying to do. The parametric curve in t of x(t), y(t) exists but if a slice for constant T0 cuts that curve in several places you have a big problem. -- Regards, Martin Brown