# wave and rider

Started by January 25, 2013
```This is the signal I hope to create:

https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534278810_133123559_n.jpg

both the frequency of the blue wave and the frequency of the red rider wave

I came up with the equation for the wave using vector calculus, but it is
unlikely that the math decoder can crunch out a signal in real time at the
press of a key.

x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
y(t) = 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))

any ideas?

Jon

```
```It doesn't loop back on itself, so you're going to have a difficult time
drawing that on an X-Y plot.

Tim

--
Deep Friar: a very philosophical monk.
Website: http://seventransistorlabs.com

> This is the signal I hope to create:
>
> https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534278810_133123559_n.jpg
>
> both the frequency of the blue wave and the frequency of the red rider
>
> I came up with the equation for the wave using vector calculus, but it
> is unlikely that the math decoder can crunch out a signal in real time
> at the press of a key.
>
> x(t) = t + (6*cos(t))*(0.5*(sin(
> 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
> y(t) = 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
>
> any ideas?
>
> Jon

```
```Tim Williams wrote:
> It doesn't loop back on itself, so you're going to have a difficult time
> drawing that on an X-Y plot.
>
> Tim
>
...just use a polarity inverter on the time axis.
```
```On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon"

>This is the signal I hope to create:
>
>https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534278810_133123559_n.jpg
>
>both the frequency of the blue wave and the frequency of the red rider wave
>
>I came up with the equation for the wave using vector calculus, but it is
>unlikely that the math decoder can crunch out a signal in real time at the
>press of a key.
>
>x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
>y(t) = 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
>
>any ideas?
>
>Jon

Backward in time?
The waves with a knot in them are the most difficult.
Try an xy scope :-)
```
```On Jan 25, 5:38=A0am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote:
> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon"
>
>
>
>
>
> >This is the signal I hope to create:
>
> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_10151353534...
>
> >both the frequency of the blue wave and the frequency of the red rider w=
ave
>
> >I came up with the equation for the wave using vector calculus, but it i=
s
> >unlikely that the math decoder can crunch out a signal in real time at t=
he
> >press of a key.
>
> >x(t) =3D t + (6*cos(t))*(0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^=
.5)))
> >y(t) =3D 6*sin(t) - (0.5*(sin( 25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5))=
)
>
> >any ideas?
>
> >Jon
>
> Backward in time?

Yeah I'm confused by what he means by signal.

> The waves with a knot in them are the most difficult.
> Try an xy scope :-)- Hide quoted text -
>
> - Show quoted text -

```
```"Jon" <no-reply@no-reply.com> wrote in

> https://sphotos-b.xx.fbcdn.net/hphotos-ash4/s480x480/2049_1015135353427
> 8810_133123559_n.jpg

Ah!! you want a signal to back and forth in time!!

At last timetravel in both directions solved!!
```
```On Fri, 25 Jan 2013 07:24:35 -0800, George Herold wrote:

> On Jan 25, 5:38&nbsp;am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote:
>> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon"
>>
>>
>>
>>
>>
>> >This is the signal I hope to create:
>>
>> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/
s480x480/2049_10151353534...
>>
>> >both the frequency of the blue wave and the frequency of the red rider
>>
>> >I came up with the equation for the wave using vector calculus, but it
>> >is unlikely that the math decoder can crunch out a signal in real time
>> >at the press of a key.
>>
>> >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t)
>> >))*(1/((1+36*((cos(t))^2))^.5))) y(t) = 6*sin(t) - (0.5*(sin(
>> >25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
>>
>> >any ideas?
>>
>> >Jon
>>
>> Backward in time?
>
> Yeah I'm confused by what he means by signal.

If it's a wiggly line on something that looks like a scope screen, then
it must be a signal.

(Jon: signals and functions are closely related.  If your signal isn't a
function in time, then it's not a signal, either.  That "signal" has more
than one value of y for most values of x.  So while it is a valid curve,
as plotted it isn't really a signal).

--
My liberal friends think I'm a conservative kook.
My conservative friends think I'm a liberal kook.
Why am I not happy that they have found common ground?

Tim Wescott, Communications, Control, Circuits & Software
http://www.wescottdesign.com
```
```
"Tim Wescott" <tim@seemywebsite.com> wrote in message
news:ltKdnY-LaNH3I5_MnZ2dnUVZ_uudnZ2d@giganews.com...
> On Fri, 25 Jan 2013 07:24:35 -0800, George Herold wrote:
>
>> On Jan 25, 5:38 am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote:
>>> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon"
>>>
>>>
>>>
>>>
>>>
>>> >This is the signal I hope to create:
>>>
>>> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/
> s480x480/2049_10151353534...
>>>
>>> >both the frequency of the blue wave and the frequency of the red rider
>>>
>>> >I came up with the equation for the wave using vector calculus, but it
>>> >is unlikely that the math decoder can crunch out a signal in real time
>>> >at the press of a key.
>>>
>>> >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t)
>>> >))*(1/((1+36*((cos(t))^2))^.5))) y(t) = 6*sin(t) - (0.5*(sin(
>>> >25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
>>>
>>> >any ideas?
>>>
>>> >Jon
>>>
>>> Backward in time?
>>
>> Yeah I'm confused by what he means by signal.
>
> If it's a wiggly line on something that looks like a scope screen, then
> it must be a signal.
>
> (Jon: signals and functions are closely related.  If your signal isn't a
> function in time, then it's not a signal, either.  That "signal" has more
> than one value of y for most values of x.  So while it is a valid curve,
> as plotted it isn't really a signal).
>
> --
> My liberal friends think I'm a conservative kook.
> My conservative friends think I'm a liberal kook.
> Why am I not happy that they have found common ground?
>
> Tim Wescott, Communications, Control, Circuits & Software
> http://www.wescottdesign.com

https://sphotos-b.xx.fbcdn.net/hphotos-ash3/s480x480/602730_10151354609363810_2113498556_n.jpg

```
```On 25/01/2013 20:19, Jon wrote:
>
>
> "Tim Wescott" <tim@seemywebsite.com> wrote in message
> news:ltKdnY-LaNH3I5_MnZ2dnUVZ_uudnZ2d@giganews.com...
>> On Fri, 25 Jan 2013 07:24:35 -0800, George Herold wrote:
>>
>>> On Jan 25, 5:38 am, Jan Panteltje <pNaonStpealm...@yahoo.com> wrote:
>>>> On a sunny day (Fri, 25 Jan 2013 01:07:26 -0500) it happened "Jon"
>>>>
>>>> >This is the signal I hope to create:
>>>>
>>>> >https://sphotos-b.xx.fbcdn.net/hphotos-ash4/
>> s480x480/2049_10151353534...

It is multivalued for various t how exactly do you expect your hardware
to output more than one voltage at a single port?
>>>>
>>>> >both the frequency of the blue wave and the frequency of the red rider
>>>>
>>>> >I came up with the equation for the wave using vector calculus, but it
>>>> >is unlikely that the math decoder can crunch out a signal in real time
>>>> >at the press of a key.
>>>>
>>>> >x(t) = t + (6*cos(t))*(0.5*(sin( 25*sin(t)
>>>> >))*(1/((1+36*((cos(t))^2))^.5))) y(t) = 6*sin(t) - (0.5*(sin(
>>>> >25*sin(t) ))*(1/((1+36*((cos(t))^2))^.5)))
>>>>
>>>> >any ideas?
>>>>
>>>> >Jon
>>>>
>>>> Backward in time?
>>>
>>> Yeah I'm confused by what he means by signal.
>>
>> If it's a wiggly line on something that looks like a scope screen, then
>> it must be a signal.
>>
>> (Jon: signals and functions are closely related.  If your signal isn't a
>> function in time, then it's not a signal, either.  That "signal" has more
>> than one value of y for most values of x.  So while it is a valid curve,
>> as plotted it isn't really a signal).
>>
>> --
>> My liberal friends think I'm a conservative kook.
>> My conservative friends think I'm a liberal kook.
>> Why am I not happy that they have found common ground?
>>
>> Tim Wescott, Communications, Control, Circuits & Software
>> http://www.wescottdesign.com
>
> https://sphotos-b.xx.fbcdn.net/hphotos-ash3/s480x480/602730_10151354609363810_2113498556_n.jpg

That one is carefully chosen so that y(t) vs x(t) has only one value.

You need to think very carefully about what it is you are trying to do.
The parametric curve in t of x(t), y(t) exists but if a slice for
constant T0 cuts that curve in several places you have a big problem.

--
Regards,
Martin Brown
```