> Uwe Bonnes <bon@hertz.ikp.physik.tu-darmstadt.de> wrote:
>
>>>
>>> LM2662 has a splitter mode.
>
> switched capacitor is noisy.
>
>> TLE2426
>
> This is excellent. A simple buffer could be added if more current is
> required.
The Notes section of my Audio Mixer Amplifier contains some pertinent
information: <https://crcomp.net/mixeramp/index.php#Notes> . Its Virtual
Ground Circuits link covers the TLE2426 as well as other devices.
Danke,
--
Don, KB7RPU, https://www.qsl.net/kb7rpu
There was a young lady named Bright Whose speed was far faster than light;
She set out one day In a relative way And returned on the previous night.
Reply by Mike Monett VE3BTI●December 1, 20222022-12-01
John Larkin <jlarkin@highlandsnipmetechnology.com> wrote:
> On Thu, 1 Dec 2022 13:44:26 -0000 (UTC), Mike Monett VE3BTI
> <spamme@not.com> wrote:
>
>>Spehro, I don't know if you are still on SED, but if so, I'd like to ask a
>>question.
>>
>>A long time ago, Jim Thompson posted a circuit and asked if anyone could
>>figure it out. You analysed it and said it was a voltage splitter, that would
>>split a voltage in half.
>>
>>Do you happen to remember the circuit, or know where I can find it?
>>
>>Thanks,
>>
>>Mike
>
> LM2662 has a splitter mode.
>
On Thu, 1 Dec 2022 13:44:26 -0000 (UTC), Mike Monett VE3BTI
<spamme@not.com> wrote:
>Spehro, I don't know if you are still on SED, but if so, I'd like to ask a
>question.
>
>A long time ago, Jim Thompson posted a circuit and asked if anyone could
>figure it out. You analysed it and said it was a voltage splitter, that would
>split a voltage in half.
>
>Do you happen to remember the circuit, or know where I can find it?
>
>Thanks,
>
>Mike
LM2662 has a splitter mode.
Reply by Mike Monett VE3BTI●December 1, 20222022-12-01
Spehro, I don't know if you are still on SED, but if so, I'd like to ask a
question.
A long time ago, Jim Thompson posted a circuit and asked if anyone could
figure it out. You analysed it and said it was a voltage splitter, that would
split a voltage in half.
Do you happen to remember the circuit, or know where I can find it?
Thanks,
Mike
--
MRM